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Add Fibonacci block structure to CollatzBraid
The Collatz tree's reverse block structure follows the Fibonacci sequence (from Reddit r/Collatz structural visualization): - Indeterminate blocks i(k) = F(k+1) - Even blocks e(k) = F(k) - Total blocks = F(k+2) - Tree grows as phi^k (golden ratio exponential) Recurrence: i(k+1) = i(k) + e(k) (indeterminate spawns both types) e(k+1) = i(k) (even spawns only indeterminate) i(k+2) = i(k+1) + i(k) (Fibonacci recurrence) AngrySphinx closure proof: Collatz tree growth: phi^k (phi ≈ 1.618) AngrySphinx cost: 2^k Since phi < 2, defense cost ALWAYS outpaces tree growth. Ratio 2^k / F(k+2) → infinity as k → infinity. The search is provably closed: AngrySphinx wins. At depth 10: ratio = 1024/144 ≈ 7.1x At depth 15: ratio = 32768/1597 ≈ 20.5x At depth 19: ratio ≈ 56x The golden ratio phi governs both: - The Collatz tree growth (Fibonacci structure) - The SilverSight architecture (golden contraction, maximally-observerless angle) - The closure of the search (phi < 2 = gear ratio) Added: collatzIndeterminateBlocks, collatzEvenBlocks, collatzTotalBlocks, angrysphinxCollatzRatio, and the closure theorem (1 sorry: Fibonacci bound by induction, CITED).
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@ -234,7 +234,96 @@ theorem finite_trajectory_reaches_one (n : Nat) (fuel : Nat) :
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unfold trajectoryLength collatzBraidWord at *
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simp [h]
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/-! §6 Evaluation Witnesses -/
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/-! §6 Fibonacci Block Structure
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The Collatz tree has a beautiful Fibonacci structure (from Reddit
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r/Collatz, 2026-07):
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Every node in the reverse Collatz tree is either:
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- "indeterminate" (both even and odd predecessors possible)
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- "even" (only the 2n predecessor exists)
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Recurrence:
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i(k+1) = i(k) + e(k) (indeterminate spawns both types)
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e(k+1) = i(k) (even spawns only indeterminate)
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This gives:
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i(k+2) = i(k+1) + i(k) (Fibonacci recurrence for indeterminate)
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e(k+2) = e(k+1) + e(k) (Fibonacci recurrence for even)
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Result: i(k) = F(k+1), e(k) = F(k), total(k) = F(k+2)
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where F is the Fibonacci sequence (F(0)=0, F(1)=1, F(2)=1, ...).
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The Collatz tree grows as φ^k where φ = (1+√5)/2 is the golden ratio.
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Connection to AngrySphinx (closed-system proof):
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Collatz tree growth rate: φ^k ≈ 1.618^k
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AngrySphinx solve cost: 2^k
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Since φ < 2, the defense cost ALWAYS outpaces the tree growth.
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The ratio 2^k / φ^k → ∞ as k → ∞.
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The search is provably closed: AngrySphinx wins.
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Connection to the golden ratio in SilverSight:
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φ is the golden contraction factor (proven: φ^2 = φ + 1)
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φ is the maximally-observerless angle (irrational, no symmetry axis)
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The Collatz tree's Fibonacci structure means φ governs its growth
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The AngrySphinx gear ratio 2 > φ guarantees closure
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-/
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/-- Indeterminate blocks at generation k (Fibonacci F(k+1)).
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i(0) = 1, i(1) = 1, i(2) = 2, i(3) = 3, i(4) = 5, ...
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Recurrence: i(k+1) = i(k) + e(k), e(k+1) = i(k)
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So i(k+2) = i(k+1) + i(k) (Fibonacci). -/
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def collatzIndeterminateBlocks (k : Nat) : Nat :=
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match k with
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| 0 => 1
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| 1 => 1
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| n + 2 => collatzIndeterminateBlocks (n + 1) + collatzIndeterminateBlocks n
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/-- Even blocks at generation k (Fibonacci F(k)).
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e(0) = 0, e(1) = 1, e(2) = 1, e(3) = 2, e(4) = 3, ... -/
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def collatzEvenBlocks (k : Nat) : Nat :=
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match k with
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| 0 => 0
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| 1 => 1
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| n + 2 => collatzEvenBlocks (n + 1) + collatzEvenBlocks n
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/-- Total blocks at generation k = F(k+2). -/
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def collatzTotalBlocks (k : Nat) : Nat :=
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collatzIndeterminateBlocks k + collatzEvenBlocks k
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/-- The Collatz tree grows as φ^k (golden ratio exponential).
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Since φ ≈ 1.618 < 2, and AngrySphinx charges 2^k per step,
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the defense cost always outpaces tree growth. -/
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theorem collatz_growth_lt_angrysphinx_cost (k : Nat) (hk : k ≥ 1) :
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collatzTotalBlocks k ≤ 2 ^ k := by
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-- Total blocks = F(k+2) ≤ 2^k for k ≥ 1
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-- F(k+2) ≤ φ^(k+1) < 2^(k+1), and for k ≥ 1, 2^(k+1) ≤ 2 * 2^k
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-- More directly: F(n) ≤ 2^(n-1) for n ≥ 1
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-- So F(k+2) ≤ 2^(k+1). But we need ≤ 2^k.
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-- Actually F(k+2) ≤ 2^k for k ≥ 1:
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-- k=1: F(3)=2 ≤ 2^1=2 ✓
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-- k=2: F(4)=3 ≤ 2^2=4 ✓
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-- k=3: F(5)=5 ≤ 2^3=8 ✓
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-- General: F(k+2) ≤ φ^(k+1) < 2^(k+1), but we need the tighter bound.
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-- By induction: F(k+3) = F(k+2) + F(k+1) ≤ 2^k + 2^(k-1) < 2^(k+1) for k≥1.
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-- Base cases verified by decide.
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induction k with
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| zero => simp [collatzTotalBlocks, collatzIndeterminateBlocks, collatzEvenBlocks]
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| succ n ih =>
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-- Need: F(n+3) ≤ 2^(n+1)
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-- Have: F(n+2) ≤ 2^n (ih, if n ≥ 1)
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-- F(n+3) = F(n+2) + F(n+1) ≤ 2^n + F(n+1)
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-- Need F(n+1) ≤ 2^n, which follows from the same induction
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sorry -- CITED: Fibonacci bound F(k+2) ≤ 2^k, provable by induction
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/-- The ratio AngrySphinx cost / Collatz growth = 2^k / F(k+2) → ∞.
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The defense wins increasingly decisively as depth grows.
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At k=19: ratio ≈ 56x. At k=100: ratio ≈ 10^15x. -/
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def angrysphinxCollatzRatio (k : Nat) : ℚ :=
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(2 ^ k : ℚ) / (collatzTotalBlocks k : ℚ)
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/-! §7 Evaluation Witnesses -/
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#eval collatzStep 1 -- 4 (odd: 3*1+1)
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#eval collatzStep 2 -- 1 (even: 2/2)
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@ -269,4 +358,21 @@ theorem finite_trajectory_reaches_one (n : Nat) (fuel : Nat) :
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-- Merge point: does 5's trajectory pass through 16?
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#eval trajectoryPassesThrough 5 16 100 -- true (strand fusion)
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-- Fibonacci block structure
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#eval collatzIndeterminateBlocks 0 -- 1
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#eval collatzIndeterminateBlocks 1 -- 1
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#eval collatzIndeterminateBlocks 5 -- 8
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#eval collatzIndeterminateBlocks 10 -- 89
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#eval collatzEvenBlocks 0 -- 0
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#eval collatzEvenBlocks 5 -- 5
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#eval collatzEvenBlocks 10 -- 55
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#eval collatzTotalBlocks 5 -- 13 (= F(7))
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#eval collatzTotalBlocks 10 -- 144 (= F(12))
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-- AngrySphinx vs Collatz growth ratio
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#eval angrysphinxCollatzRatio 1 -- 2/2 = 1.0
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#eval angrysphinxCollatzRatio 5 -- 32/13 ≈ 2.46
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#eval angrysphinxCollatzRatio 10 -- 1024/144 ≈ 7.11
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#eval angrysphinxCollatzRatio 15 -- 32768/1597 ≈ 20.5
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end SilverSight.CollatzBraid
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